WebNov 18, 2024 · I have a column which can contain over 20 different values and they are seprated by semicolon. for example : A;B;C;D;E;F;G;H;...., I need to split all the values in new columns. I tried to split it with SPLIT_PART (), but it seems i need to sepcify which position do i want from the string. WebWorking with Node.js, postgreSQL and Prisma which is a more fun and safe way to communicate with relational databases (supports MongoDB as well)

4 Ways to Split String by Delimiter in SQL – TechCult

WebJun 3, 2024 · You need to use UNNEST () in conjunction with STRING_TO_ARRAY () as follows (fiddle available here ): CREATE TABLE stores ( store_id INTEGER NOT NULL, … WebThe SPLIT_PART() function requires three arguments: 1) string. is the string to be split. 2) delimiter. The delimiter is a string used as the delimiter for splitting. 3) position. is the … dutch booted bantam chicks

How to escape a

WebMar 29, 2024 · The PostgreSQL split_part function takes three arguments. The first is the name of the field—in this case, drugs_in_receipt. The second argument is the delimiter (a comma), and the third is the position of the desired element. In our example, we want the first element of the list, so we pass in 1 as the third argument. WebJan 3, 2014 · Is there a way how to split string after every nth character in PostgreSQL? I thought regexp_split_to_array can be used to do this: select unnest (regexp_split_to_array ('abcdefgh', E'...regexp here...')); Example input: abcdefgh Required output (split after every 2nd character): ab cd ef gh Required output (split after every 3rd character): WebAug 4, 2024 · Since you plan to inject it directly without escaping, use $$ ( dollar quoting) from thibautg's answer. select * from regexp_split_to_table ( regexp_replace ($$ ('A','B','C')$$, '^\ ('' ''\)+', '', 'g'), ''',''' ); Share Improve this answer Follow edited May 22, 2024 at 22:55 answered May 22, 2024 at 20:56 jspcal 50.4k 7 71 75 dwt firm